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Quadratic Equations Class 10: Practice Questions

Solve Class 10 quadratic equations by factorisation and the quadratic formula. Includes discriminant checks, word problems and explained answers.

About 3 min readReviewed by Codex (AI content review)Syllabus NCERT 2026–27 reprint (selected topics)Updated 4/9/2026

A quadratic equation has the form ax² + bx + c = 0 with a ≠ 0. First put every term on one side and simplify. Try factorisation when the factors are easy to spot; otherwise use the quadratic formula. Check a word-problem answer against the context as well as the equation.

Choose a method

MethodWhen it helps
FactorisationYou can find factor pairs that give the middle term.
Quadratic formulaFactor pairs are inconvenient or roots involve square roots.
Discriminant D = b² − 4acYou need the number of real roots before solving.

The quadratic formula is x = (−b ± √(b² − 4ac))/(2a). If D > 0 there are two distinct real roots; if D = 0 they are equal; if D < 0 there are no real roots.

Worked practice

1. Solve x² − 9x + 20 = 0

  1. 1(x − 4)(x − 5) = 0, so x = 4 or 5.
  2. 2Check x = 4: 16 − 36 + 20 = 0.

2. Solve 2x² + x − 6 = 0

  1. 1Split x as 4x − 3x: 2x(x + 2) − 3(x + 2) = 0.
  2. 2(2x − 3)(x + 2) = 0, so x = 3/2 or −2.

3. Solve x² − 4x + 1 = 0

  1. 1a = 1, b = −4, c = 1. D = 16 − 4 = 12.
  2. 2x = (4 ± √12)/2 = 2 ± √3. Keep the exact form unless a decimal is requested.

4. How many real roots does 3x² + 2x + 5 = 0 have?

  1. 1D = 2² − 4 × 3 × 5 = −56.
  2. 2There are no real roots. A negative discriminant does not mean the equation has degree less than two.

A rectangle word problem

5. A rectangle has area 48 cm² and is 2 cm longer than it is wide

  1. 1Let width be x cm. Then length is x + 2 cm and x(x + 2) = 48.
  2. 2x² + 2x − 48 = (x + 8)(x − 6) = 0.
  3. 3The algebraic roots are −8 and 6, but width must be positive. Width = 6 cm; length = 8 cm. Check area = 48 cm².

Try first, then check

  • 6. x² + 5x + 6 = 0. Answer: −2 and −3.
  • 7. 4x² − 12x + 9 = 0. Answer: x = 3/2, a repeated root since D = 0.
  • 8. The product of two consecutive positive integers is 72. Answer: 8 and 9; n(n + 1) = 72 gives (n + 9)(n − 8) = 0.

Avoid these errors

The entire numerator, including the square-root term, is divided by 2a. Use parentheses when entering the formula into a calculator. Never discard a negative root automatically: exclude it only when the problem context demands a positive quantity, such as a length.

Topic reference: NCERT Mathematics, Quadratic Equations

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